3(n-2)^2-13(n-2)+4=0

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Solution for 3(n-2)^2-13(n-2)+4=0 equation: 



3(n-2)^2-13(n-2)+4=0

We multiply parentheses

3(n-2)^2-13n+26+4=0

We add all the numbers together, and all the variables

-13n+3(n-2)^2+30=0

We move all terms containing n to the left, all other terms to the right

-13n+3(n-2)^2=-30

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